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	Show that( b^2c^2+c^2a^2+a^2b^2) is greater then equals abc(a+b+c) where a, b, c are different... (concepts \u0026 Methods) View
	a+b+c=0 then show that 1/(2a^2+bc)+1/(2b^2+ca)+1/(2c^2+ab)=0 (YOGI MATH TUTORIAL) View
	Prove that : `\|b c-c^2c a-^2a b-c^2c a-b^2a b-c^2b c-a^2a b-c^2b c-a^2c a-b^2\|=\|a b c b c a c a ... (Doubtnut) View
	Show that:det [[a - b - c, 2a, 2a], [2b, b - c - a, 2b], [2c, 2c, c - a - b]] = (a + b + c) ^ 3 (Mathematics Untold) View
	Let a, b and c be such that a + b + c= 0 and P=a^(2)/(2a^(2)+ bc) + b^(2)/(2b^(2) + ca) + c^(2)/... (Doubtnut) View
	If a+b+c=0, then what is the value of (a^(2)+b^(2)+c^(2))/((a-b)^(2)+(b-c)^(2)+(c-a)^(2)) \| CL... (Doubtnut) View
	If a+b+c=0, then prove that a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab) =1. (Mathematics for Mankind- online class by DPM) View
	In a ABC, prove that 4(b c ·cos ^2A/2+c a ·cos ^2B/2+a b ·cos ^2C/2)=(a+b+c)^2 (PW Solutions) View
	Without expanding show that `\|[b^2c^2,b c, b+c],[c^2a^2,c a ,c+a ],[a^2b^2,a b ,a+b]\|=0` (Doubtnut) View
	`\|[a^2,bc,c^2+ca] , [a^2+ab,b^2,ca] , [ab,b^2+bc,c^2]\|=4a^2b^2c^2` (Doubtnut) View